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Field Power

Field Power

Dynaudio Acoustics BM 5A BM5A Powered Studio Monitors 100W Active Near field
Dynaudio Acoustics BM 5A BM5A Powered Studio Monitors 100W Active Near field
Paypal   US $763.87
CARVER PM 600 Magnetic Field Power Amplifier Grade B
CARVER PM 600 Magnetic Field Power Amplifier Grade B
Paypal   US $349.50
CARVER M10t Magnetic Field Power Amplifier
CARVER M10t Magnetic Field Power Amplifier
Paypal   US $398.50
KRK Rokit RP10 3 Mid Field 3 Way Powered Studio Monitor 10 Inch
KRK Rokit RP10 3 Mid Field 3 Way Powered Studio Monitor 10 Inch
Paypal   US $499.00
Carver PM 120 Magnetic Field Power Amplifier Amp NICE
Carver PM 120 Magnetic Field Power Amplifier Amp NICE
Paypal   US $55.00
Peavey PMA 70 70 rms Near Field power amp mint Condition
Peavey PMA 70 70 rms Near Field power amp mint Condition
Paypal   US $30.00
Carver PM 15 Magnetic Field Power Amplifier
Carver PM 15 Magnetic Field Power Amplifier
Paypal   US $46.00
Pro Audio Equipment Blog

How do you prove that a power of an algebraic number over a field is also an algebraic number?

This question is in Abstract Algebra.
If you have an algebraic element 'a' over a field F, and some integer n, how can you prove 'a to the n power' is also an algebraic element over F?

I'll assume you want n to be a positive integer. Consider F[a], the field obtained by adjoining a. Then a^n is in F[a] and the index of F[a] over F is finite. But every element of a field of finite index over F will be algebraic over F.

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